Reasoning about Uncertainty
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9.1 This exercise shows that the plausibility measures Pl1 and Pl2 considered in Section 9.1 can be obtained using the construction preceding Theorem 8.4.12.
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Show that Pl1 is the plausibility measure obtained from the probability sequence (μ1, μ2, μ3, …) defined in Section 9.1, using the construction preceding Theorem 8.4.12.
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Define a probability sequence (μ1′, μ2′, μ3′, …) from which Pl2 is obtained using the construction preceding Theorem 8.4.12.
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9.2 Prove Proposition 9.1.1.
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9.3 Prove Proposition 9.1.2.
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9.4 Prove Proposition 9.1.3.
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9.5 Show that in an SDP system (
, a, π), if the prior Pla on runs that generates a satisfies Pl4 and Pl5, then so does the agent's plausibility space Pla(r, m) at each point (r, m). -
9.6 Show that a BCS is a synchronous system satisfying CONS in which the agent has perfect recall.
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* 9.7 This exercise expands on Example 9.3.1 and shows that AGM-style belief revision can be understood as conditioning, using a conditional probability measure. As in Example 9.3.1, fix a finite set Φ of primitive propositions and a consequence relation ⊢
for Prop(Φ). -
Show that there is a single formula σ such that ⊢
iff σ ↠ φ is a propositional tautology. -
As in Example 9.3.1, let M = (W, 2W, 2W − ∅, μ, π) be a simple conditional probability structure, where π is such that (i) (M, w) ⊨ σ for all w ∈ W and (ii) if σ ∧ ψ is satisfiable, then there is some world w ∈ W such that (M, w) ⊨ ψ. Let K ={ψ : μ([[ψ]]M) = 1}. If [[φ]]M ≠ ∅, define K ∘ φ ={ψ : μ([[ψ]]M|[[φ]]M) = 1}; if [[φ]]M = ∅, define K ∘ φ = Cl(false). Show that this definition of revision satisfies R1–8.
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Given a revision operator ∘ satisfying R1–8 (with respect to ⊢
and a belief set K ≠ Cl(false), show that there exists a simple conditional probability space MK = (W, 2W, 2W − ∅, μK, π) such that (i) K ={ψ : μ([[ψ]]M) = 1} and (ii) if K ∘ φ ≠ Cl(false), then K ∘ φ ={ψ : μ([[ψ]]M | [[φ]]M) = 1}.
Note that part (b) essentially shows that every conditional probability measure defines a belief revision operator, and part (c) essentially shows that every belief revision operator can be viewed as arising from a conditional probability measure on an appropriate space.
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9.8 Construct a BCS satisfying REV1 and REV2 that has the properties required in Example 9.3.3. Extend this example to one that satisfies REV1 and REV2 but violates R7 and R8.
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9.9 Show that if BCS1–3 hold and sa φ is a local state in 퓙, then
[sa] ∩ [φ]∊ ′. -
9.10 Prove Lemma 9.3.4.
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9.11 Show that 퓙†1 ∊
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* 9.12 Fill in the missing details of Theorem 9.3.5. In particular, show that the definition of ∘s, a satisfies R1–8 if K ≠ Bel(퓙, sa) or sa φ is not a local state in 퓙, and provide the details of the proof that R7 and R8 hold if K = Bel(퓙, sa) and sa φ is a local state in 퓙.
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9.13 Show that the BCS 퓙 constructed in Example 9.3.6 is in
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* 9.14 Prove Theorem 9.3.7.
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9.15 Prove Theorem 9.4.1.
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* 9.16 Complete the proof of Theorem 9.4.2(b) by showing that R7 and R8 hold.
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9.17 This exercise relates the postulates and property (9.9).
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Show that (9.9) follows from R3′, R4′, R7′, and R8′.
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Show that if BS satisfies R2′ and ψ ∉ BS(E ∘ φ), then ⊬
e (φ ∧ ψ). -
Describe a system I that satisfies (9.9) and not R9′.
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Show that R8′ follows from R2′, R4′ and R9′.
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* 9.18 Complete the proof of Theorem 9.5.1. Moreover, show that (∘, BS퓙) satisfies R1′–9′, thus proving Theorem 9.5.2.
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* 9.19 Complete the proof of Theorem 9.5.3.
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* 9.20 Complete the proof of Theorem 9.6.2. (The difficulty here, as suggested in the text, is making Pl′
algebraic.)
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