PHP Cookbook: Solutions and Examples for PHP Programmers

25.1.1. Problem

You want to process arguments passed on the command line.

25.1.2. Solution

Look in $argc for the number of arguments and $argv for their values. The first argument, $argv[0], is the name of script that is being run:

if ($argc != 2) { die("Wrong number of arguments: I expect only 1."); } $size = filesize($argv[1]); print "I am $argv[0] and report that the size of "; print "$argv[1] is $size bytes.";

25.1.3. Discussion

In order to set options based on flags passed from the command line, loop through $argv from 1 to $argc, as shown in Example 25-1.

Parsing commmand-line arguments

<?php for ($i = 1; $i < $argc; $i++) { switch ($argv[$i]) { case '-v': // set a flag $verbose = true; break; case '-c': // advance to the next argument $i++; // if it's set, save the value if (isset($argv[$i])) { $config_file = $argv[$i]; } else { // quit if no filename specified die("Must specify a filename after -c"); } break; case '-q': $quiet = true; break; default: die('Unknown argument: '.$argv[$i]); break; } } ?>

In this example, the -v and -q arguments are flags that set $verbose and $quiet, but the -c argument is expected to be followed by a string. This string is assigned to $config_file.

25.1.4. See Also

25.2 for more parsing arguments with getopt; documentation on $argc and $argv at http://www.php.net/reserved.variables.

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