Binding a Block Argument to a Variable
Problem
You've written a method that takes a code block, but it's not enough for you to simply call the block with yield. You need to somehow bind the code block to a variable, so you can manipulate the block directly. Most likely, you need to pass it as the code block to another method.
Solution
Put the name of the block variable at the end of the list of your method's arguments. Prefix it with an ampersand so that Ruby knows it's a block argument, not a regular argument.
An incoming code block will be converted into a Proc object and bound to the block variable. You can pass it around to other methods, call it directly using call, or yield to it as though you'd never bound it to a variable at all. All three of the following methods do exactly the same thing:
def repeat(n) n.times { yield } if block_given? end repeat(2) { puts "Hello." } # Hello. # Hello. def repeat(n, &block) n.times { block.call } if block end repeat(2) { puts "Hello." } # Hello. # Hello. def repeat(n, &block) n.times { yield } if block end repeat(2) { puts "Hello." } # Hello. # Hello.
Discussion
If &foo is the name of a method's last argument, it means that the method accepts an optional block named foo. If the caller chooses to pass in a block, it will be made available as a Proc object bound to the variable foo. Since it is an optional argument, foo will be nil if no block is actually passed in. This frees you from having to call Kernel#block_given? to see whether or not you got a block.
When you call a method, you can pass in any Proc object as the code block by prefixing the appropriate variable name with an ampersand. You can even do this on a Proc object that was originally passed in as a code block to your method.
Many methods for collections, like each, select, and detect, accept code blocks. It's easy to wrap such methods when your own methods can bind a block to a variable. Here, a method called biggest finds the largest element of a collection that gives a true result for the given block:
def biggest(collection, &block) block ? collection.select(&block).max : collection.max end array = [1, 2, 3, 4, 5] biggest(array) {|i| i < 3} # => 2 biggest(array) {|i| i != 5 } # => 4 biggest(array) # => 5
This is also very useful when you need to write a frontend to a method that takes a block. Your wrapper method can bind an incoming code block to a variable, then pass it as a code block to the other method.
This code calls a code block limit times, each time passing in a random number between min and max:
def pick_random_numbers(min, max, limit) limit.times { yield min+rand(max+1) } end
This code is a wrapper method for pick_random_numbers. It calls a code block 6 times, each time with a random number from 1 to 49:
def lottery_style_numbers(&block) pick_random_numbers(1, 49, 6, &block) end lottery_style_numbers { |n| puts "Lucky number: #{n}" } # Lucky number: 20 # Lucky number: 39 # Lucky number: 41 # Lucky number: 10 # Lucky number: 41 # Lucky number: 32
The code block argument must always be the very last argument defined for a method. This means that if your method takes a variable number of arguments, the code block argument goes after the container for the variable arguments:
def invoke_on_each(*args, &block) args.each { |arg| yield arg } end invoke_on_each(1, 2, 3, 4) { |x| puts x ** 2 } # 1 # 4 # 9 # 16
See Also
- Recipe 8.11, "Accepting or Passing a Variable Number of Arguments"
- Recall from the chapter introduction that in Ruby 1.8, a code block cannot itself take a block argument; this is fixed in Ruby 1.9